Integrand size = 21, antiderivative size = 134 \[ \int (a+a \sec (c+d x))^3 \sin ^5(c+d x) \, dx=\frac {5 a^3 \cos (c+d x)}{d}+\frac {5 a^3 \cos ^2(c+d x)}{2 d}-\frac {a^3 \cos ^3(c+d x)}{3 d}-\frac {3 a^3 \cos ^4(c+d x)}{4 d}-\frac {a^3 \cos ^5(c+d x)}{5 d}-\frac {a^3 \log (\cos (c+d x))}{d}+\frac {3 a^3 \sec (c+d x)}{d}+\frac {a^3 \sec ^2(c+d x)}{2 d} \]
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Time = 0.20 (sec) , antiderivative size = 134, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {3957, 2915, 12, 90} \[ \int (a+a \sec (c+d x))^3 \sin ^5(c+d x) \, dx=-\frac {a^3 \cos ^5(c+d x)}{5 d}-\frac {3 a^3 \cos ^4(c+d x)}{4 d}-\frac {a^3 \cos ^3(c+d x)}{3 d}+\frac {5 a^3 \cos ^2(c+d x)}{2 d}+\frac {5 a^3 \cos (c+d x)}{d}+\frac {a^3 \sec ^2(c+d x)}{2 d}+\frac {3 a^3 \sec (c+d x)}{d}-\frac {a^3 \log (\cos (c+d x))}{d} \]
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Rule 12
Rule 90
Rule 2915
Rule 3957
Rubi steps \begin{align*} \text {integral}& = -\int (-a-a \cos (c+d x))^3 \sin ^2(c+d x) \tan ^3(c+d x) \, dx \\ & = \frac {\text {Subst}\left (\int \frac {a^3 (-a-x)^2 (-a+x)^5}{x^3} \, dx,x,-a \cos (c+d x)\right )}{a^5 d} \\ & = \frac {\text {Subst}\left (\int \frac {(-a-x)^2 (-a+x)^5}{x^3} \, dx,x,-a \cos (c+d x)\right )}{a^2 d} \\ & = \frac {\text {Subst}\left (\int \left (-5 a^4-\frac {a^7}{x^3}+\frac {3 a^6}{x^2}-\frac {a^5}{x}+5 a^3 x+a^2 x^2-3 a x^3+x^4\right ) \, dx,x,-a \cos (c+d x)\right )}{a^2 d} \\ & = \frac {5 a^3 \cos (c+d x)}{d}+\frac {5 a^3 \cos ^2(c+d x)}{2 d}-\frac {a^3 \cos ^3(c+d x)}{3 d}-\frac {3 a^3 \cos ^4(c+d x)}{4 d}-\frac {a^3 \cos ^5(c+d x)}{5 d}-\frac {a^3 \log (\cos (c+d x))}{d}+\frac {3 a^3 \sec (c+d x)}{d}+\frac {a^3 \sec ^2(c+d x)}{2 d} \\ \end{align*}
Time = 0.30 (sec) , antiderivative size = 108, normalized size of antiderivative = 0.81 \[ \int (a+a \sec (c+d x))^3 \sin ^5(c+d x) \, dx=-\frac {a^3 (-120-12350 \cos (c+d x)-2074 \cos (3 (c+d x))-330 \cos (4 (c+d x))+82 \cos (5 (c+d x))+45 \cos (6 (c+d x))+6 \cos (7 (c+d x))+960 \log (\cos (c+d x))+15 \cos (2 (c+d x)) (31+64 \log (\cos (c+d x)))) \sec ^2(c+d x)}{1920 d} \]
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Time = 2.11 (sec) , antiderivative size = 172, normalized size of antiderivative = 1.28
method | result | size |
derivativedivides | \(\frac {a^{3} \left (\frac {\sin \left (d x +c \right )^{6}}{2 \cos \left (d x +c \right )^{2}}+\frac {\sin \left (d x +c \right )^{4}}{2}+\sin \left (d x +c \right )^{2}+2 \ln \left (\cos \left (d x +c \right )\right )\right )+3 a^{3} \left (\frac {\sin \left (d x +c \right )^{6}}{\cos \left (d x +c \right )}+\left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )\right )+3 a^{3} \left (-\frac {\sin \left (d x +c \right )^{4}}{4}-\frac {\sin \left (d x +c \right )^{2}}{2}-\ln \left (\cos \left (d x +c \right )\right )\right )-\frac {a^{3} \left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )}{5}}{d}\) | \(172\) |
default | \(\frac {a^{3} \left (\frac {\sin \left (d x +c \right )^{6}}{2 \cos \left (d x +c \right )^{2}}+\frac {\sin \left (d x +c \right )^{4}}{2}+\sin \left (d x +c \right )^{2}+2 \ln \left (\cos \left (d x +c \right )\right )\right )+3 a^{3} \left (\frac {\sin \left (d x +c \right )^{6}}{\cos \left (d x +c \right )}+\left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )\right )+3 a^{3} \left (-\frac {\sin \left (d x +c \right )^{4}}{4}-\frac {\sin \left (d x +c \right )^{2}}{2}-\ln \left (\cos \left (d x +c \right )\right )\right )-\frac {a^{3} \left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )}{5}}{d}\) | \(172\) |
parallelrisch | \(\frac {a^{3} \left (960 \left (1+\cos \left (2 d x +2 c \right )\right ) \ln \left (\sec \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )-960 \left (1+\cos \left (2 d x +2 c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )-960 \left (1+\cos \left (2 d x +2 c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )-45 \cos \left (6 d x +6 c \right )-6 \cos \left (7 d x +7 c \right )+12350 \cos \left (d x +c \right )+6733 \cos \left (2 d x +2 c \right )+2074 \cos \left (3 d x +3 c \right )+330 \cos \left (4 d x +4 c \right )-82 \cos \left (5 d x +5 c \right )+7318\right )}{960 d \left (1+\cos \left (2 d x +2 c \right )\right )}\) | \(173\) |
parts | \(-\frac {a^{3} \left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )}{5 d}+\frac {a^{3} \left (\frac {\sin \left (d x +c \right )^{6}}{2 \cos \left (d x +c \right )^{2}}+\frac {\sin \left (d x +c \right )^{4}}{2}+\sin \left (d x +c \right )^{2}+2 \ln \left (\cos \left (d x +c \right )\right )\right )}{d}+\frac {3 a^{3} \left (-\frac {\sin \left (d x +c \right )^{4}}{4}-\frac {\sin \left (d x +c \right )^{2}}{2}-\ln \left (\cos \left (d x +c \right )\right )\right )}{d}+\frac {3 a^{3} \left (\frac {\sin \left (d x +c \right )^{6}}{\cos \left (d x +c \right )}+\left (\frac {8}{3}+\sin \left (d x +c \right )^{4}+\frac {4 \sin \left (d x +c \right )^{2}}{3}\right ) \cos \left (d x +c \right )\right )}{d}\) | \(180\) |
norman | \(\frac {\frac {8 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{6}}{d}+\frac {224 a^{3}}{15 d}-\frac {2 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{12}}{d}-\frac {6 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{10}}{d}-\frac {8 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}}{3 d}+\frac {134 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{15 d}+\frac {214 a^{3} \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{5 d}}{\left (-1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{2} \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{5}}+\frac {a^{3} \ln \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )}{d}-\frac {a^{3} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{d}-\frac {a^{3} \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{d}\) | \(217\) |
risch | \(i a^{3} x -\frac {7 a^{3} {\mathrm e}^{3 i \left (d x +c \right )}}{96 d}+\frac {7 a^{3} {\mathrm e}^{2 i \left (d x +c \right )}}{16 d}+\frac {37 a^{3} {\mathrm e}^{i \left (d x +c \right )}}{16 d}+\frac {37 a^{3} {\mathrm e}^{-i \left (d x +c \right )}}{16 d}+\frac {7 a^{3} {\mathrm e}^{-2 i \left (d x +c \right )}}{16 d}-\frac {7 a^{3} {\mathrm e}^{-3 i \left (d x +c \right )}}{96 d}+\frac {2 i a^{3} c}{d}+\frac {2 a^{3} \left (3 \,{\mathrm e}^{3 i \left (d x +c \right )}+{\mathrm e}^{2 i \left (d x +c \right )}+3 \,{\mathrm e}^{i \left (d x +c \right )}\right )}{d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{2}}-\frac {a^{3} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{d}-\frac {a^{3} \cos \left (5 d x +5 c \right )}{80 d}-\frac {3 a^{3} \cos \left (4 d x +4 c \right )}{32 d}\) | \(228\) |
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Time = 0.27 (sec) , antiderivative size = 130, normalized size of antiderivative = 0.97 \[ \int (a+a \sec (c+d x))^3 \sin ^5(c+d x) \, dx=-\frac {96 \, a^{3} \cos \left (d x + c\right )^{7} + 360 \, a^{3} \cos \left (d x + c\right )^{6} + 160 \, a^{3} \cos \left (d x + c\right )^{5} - 1200 \, a^{3} \cos \left (d x + c\right )^{4} - 2400 \, a^{3} \cos \left (d x + c\right )^{3} + 480 \, a^{3} \cos \left (d x + c\right )^{2} \log \left (-\cos \left (d x + c\right )\right ) + 465 \, a^{3} \cos \left (d x + c\right )^{2} - 1440 \, a^{3} \cos \left (d x + c\right ) - 240 \, a^{3}}{480 \, d \cos \left (d x + c\right )^{2}} \]
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Timed out. \[ \int (a+a \sec (c+d x))^3 \sin ^5(c+d x) \, dx=\text {Timed out} \]
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Time = 0.21 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.79 \[ \int (a+a \sec (c+d x))^3 \sin ^5(c+d x) \, dx=-\frac {12 \, a^{3} \cos \left (d x + c\right )^{5} + 45 \, a^{3} \cos \left (d x + c\right )^{4} + 20 \, a^{3} \cos \left (d x + c\right )^{3} - 150 \, a^{3} \cos \left (d x + c\right )^{2} - 300 \, a^{3} \cos \left (d x + c\right ) + 60 \, a^{3} \log \left (\cos \left (d x + c\right )\right ) - \frac {30 \, {\left (6 \, a^{3} \cos \left (d x + c\right ) + a^{3}\right )}}{\cos \left (d x + c\right )^{2}}}{60 \, d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 297 vs. \(2 (124) = 248\).
Time = 0.42 (sec) , antiderivative size = 297, normalized size of antiderivative = 2.22 \[ \int (a+a \sec (c+d x))^3 \sin ^5(c+d x) \, dx=\frac {60 \, a^{3} \log \left ({\left | -\frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} + 1 \right |}\right ) - 60 \, a^{3} \log \left ({\left | -\frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} - 1 \right |}\right ) + \frac {30 \, {\left (15 \, a^{3} + \frac {14 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac {3 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )}}{{\left (\frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} + 1\right )}^{2}} - \frac {399 \, a^{3} - \frac {1395 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac {390 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {650 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} - \frac {565 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} + \frac {137 \, a^{3} {\left (\cos \left (d x + c\right ) - 1\right )}^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}}}{{\left (\frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} - 1\right )}^{5}}}{60 \, d} \]
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Time = 13.36 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.80 \[ \int (a+a \sec (c+d x))^3 \sin ^5(c+d x) \, dx=-\frac {\frac {a^3\,{\cos \left (c+d\,x\right )}^3}{3}-5\,a^3\,\cos \left (c+d\,x\right )-\frac {5\,a^3\,{\cos \left (c+d\,x\right )}^2}{2}-\frac {3\,a^3\,\cos \left (c+d\,x\right )+\frac {a^3}{2}}{{\cos \left (c+d\,x\right )}^2}+\frac {3\,a^3\,{\cos \left (c+d\,x\right )}^4}{4}+\frac {a^3\,{\cos \left (c+d\,x\right )}^5}{5}+a^3\,\ln \left (\cos \left (c+d\,x\right )\right )}{d} \]
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